how do I write tan^2(t/2) as a function of cost, where tan^2(t/2)=f(cost)?
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Try the identity: $\displaystyle tan^{2}(u)=\frac{1-cos(2u)}{1+cos(2u)}$
thanks, I'll try that.
so.. I get 1-cost/1+cost, but then I'm rather lost again.. do i multiply both with 1-cost...?
It's entirely in terms of cosine. That's it, isn't it?. Don't you get: $\displaystyle \frac{1-cos(t)}{1+cos(t)}$?.
yeah, that's what I meant.. but if the answer's supposed to be a polynomial?
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