## Solve cos^2(...)+cos^2(...)-2 = 0 ?

anyone have any clever ideas on how to solve this for x?

$cos^2(\pi*16^x)+cos^2(\pi*16^{1-x})-2 = 0$

?
$(cos(\pi*16^x)-1)(cos(\pi*16^x)+1)=-(cos(\pi*16^{1-x})-1)(cos(\pi*16^{1-x})+1)$
?