1. ## Determine θ

How do I solve this question?

If cos θ = -5/13 and 0 θ ≤ 2π. Determine tan θ

2. ## Re: Determine θ

Use the identities $\tan^2{\theta} = \sec^2{\theta}-1$ and $\sec{\theta} = \dfrac{1}{\cos{\theta}}$

3. ## Re: Determine θ

Method 2 ... sketch reference triangles in quadrants II and III

$\cos{\theta} = \dfrac{adjacent}{hypotenuse}$

$\tan{\theta} = \dfrac{opposite}{adjacent}$