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Thread: Exact value of s in a given interval

  1. #1
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    Exact value of s in a given interval

    Find the exact value of s in the given interval that has the given circular function value.

    tan s = sqrt3
    [pi,3pi/2]
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  2. #2
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    Re: Exact value of s in a given interval

    $\arctan(\sqrt{3}) = \dfrac{\pi}{3}$

    $s\in \left[\pi, \dfrac{3\pi}{2}\right] \implies s = \pi + \arctan(\sqrt{3}) = \dfrac{4\pi}{3}$
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    Re: Exact value of s in a given interval

    can you EILI5? I'm trying to teach myself since I've gotten so far behind so any simple explanation you might be able to offer would be greatly appreciated...
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    Re: Exact value of s in a given interval

    can you EILI5?
    huh?
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    Re: Exact value of s in a given interval

    LOL explain it like I'm five.
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  6. #6
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    Re: Exact value of s in a given interval

    Quote Originally Posted by dustileigh View Post
    LOL explain it like I'm five.
    Kind of difficult to explain inverse trig functions to a five year old ... recommend you look for videos like this one that explain it better than I could do in this venue.

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