# Conditional Trigonometric Equations

• Feb 7th 2008, 03:41 PM
senna
Conditional Trigonometric Equations
$4sin^2x-3=0$

How do I find the zeros in exact values?
• Feb 7th 2008, 04:24 PM
Soroban
Hello, senna!

You've never seen one of these before?

Quote:

Solve for $x\!:\;\;4\sin^2\!x-3\:=\:0$
Just use your knowledge of algebra . . . then Trig at the end.

Add 3 to both sides: . $4\sin^2\!x \:=\:3$

Divide by 4: . $\sin^2\!x \:=\:\frac{3}{4}$

Take square roots: . $\sin x \:=\:\pm\frac{\sqrt{3}}{2}$

Can you finish it now?

• Feb 12th 2008, 08:08 PM
senna
Thanks for the help Soroban. It's practically instant now.

$
\frac{{\pi}}{3}
$
, $
\frac{{2\pi}}{3}
$
, $
\frac{{4\pi}}{3}
$
, $
\frac{{5\pi}}{3}
$