i need to solve this math problem as an homework but i cant find how to do it could you help me pls ?
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note that $\dfrac{2\sec^2{x}}{\tan^2{x}} = 2\csc^2{x}$ ... next time post trig problems in the trig forum. thanks.
ok so i would do 2csc2x - csc2x-1 = cot2x csc2x-1=cot2x 1+cot2x-1=cot2x cot2x=cot2x thanks for the helping
Originally Posted by tom1 ok so i would do 2csc^2(x) - csc^2(x)-1 = cot^2(x) csc^2(x)-1=cot^2(x) 1+cot^2(x)-1=cot^2(x) cot^2(x)=cot^2(x) ...