https://www.examinations.ie/schools/...gher_Level.pdf
I am stuck on question Q8aii ive been told that the angle is greatest vale a can have is when it makes a right angled (triangle ACF)
i wondering why this is .
https://www.examinations.ie/schools/...gher_Level.pdf
I am stuck on question Q8aii ive been told that the angle is greatest vale a can have is when it makes a right angled (triangle ACF)
i wondering why this is .
I did not read the problem carefully enough. I apologize. Consider this: Draw a line segment perpendicular to AF that intersects point C. This represents the height of the triangle. Let's call the height of the triangle $h$. We know that $\sin \alpha = \dfrac{h}{25}$. So, the bigger $h$ is, the greater $\alpha$ is. Remember that if $h>22$, then the leg $CF$ would no longer touch the ground, so the maximum height is 22cm. Now, let's define $\angle CFA = \beta$. We know that $\sin \beta = \dfrac{h}{22}$. So, $h = 22\sin \beta$. The maximum value for $h$ is reached when $\beta = 90^\circ$ since that is when $h=|CF|=22$.