If t = tan1/2Ø Then show that: sinØ = 2t/1+t^2 I have deduced that: sin2A=2tanA/1+tan^2A But am unsure how to get from the second formula to the first.
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Hey KiaraG16. Hint - Let A = 1/2.
Oh I see, so because A could equal any angle it could also equal 1/2*Theta which is why the second equation remains the same as the first?
That's basically the idea.