can't do trig! stuff like sec^2(x)-1/sec^2(x).

Help me!

more to come

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- April 29th 2006, 10:32 AMsamneed help for test monday!!!
can't do trig! stuff like sec^2(x)-1/sec^2(x).

Help me!

more to come - April 29th 2006, 10:52 AMCaptainBlackQuote:

Originally Posted by**sam**

RonL - April 29th 2006, 11:45 AMsamtrig
that's the way the prob is in my textbook

- April 29th 2006, 11:54 AMsam
it says to simplify the trigonometric expression

- April 29th 2006, 11:54 AMsam
also 1+cos(y)/1+sec(y)

- April 29th 2006, 12:22 PMCaptainBlackQuote:

Originally Posted by**sam**

If that is simpler.

RonL - April 29th 2006, 03:41 PMc_323_h
is it or

this is what i got for the first one

since

you can square both sides to get

substitute this in to get

=

can someone tell me if that dot is the correct multiplication operator on the second line? - April 29th 2006, 04:08 PMc_323_h
and for the second:

since

we have,

there are trig identities you must understand and know how to manipulate them. - April 29th 2006, 06:57 PMc_323_h
by the way, there are no unique answers, there are many different correct answers. CaptainBlack's or my answers are just fine.

- April 29th 2006, 11:41 PMCaptainBlackQuote:

Originally Posted by**sam**

(not too likely)

Now the first of these seems the most likely, but you are leaving us guessing.

If you are writing this using plain ASCII then write it as:

(1+cos(y))/(1+sec(y))

The rule is: when something is ambiguous when written in plain ASCII then

add brackets until only the intended meaning is possible.

RonL