Hi,

I'm having trouble with a proof in a course assignment. We aren't using calculus yet. The lesson covers the sine of 1 degree and describes the equations sin(x+y), cos(x+y), sin(x-y), cos(x-y), sin(2x) and cos(2x).

In one particular problem there's a step I don't understand:

Equation 1: $\displaystyle 2sin(\frac{x}{2})cos(\frac{x}{2}) + 2sin(\frac{y}{2})cos(\frac{y}{2}) = sin(x)+sin(y)$

I know from the equation for sin(2x) that:

Equation 2: $\displaystyle sin(2x) = 2sin(x)cos(x)$

but it looks as if they're dividing all the angles by 2 in this second equation. Is this just a given that will be covered in calculus later or is there some way other than calculus to derive:

Equation 3: $\displaystyle 2sin(\frac{x}{2})cos(\frac{x}{2}) = sin(x)$

I've drawn a circle with r = 1 and tried to reconcile the concept that, for any point on the circle, half the angle of elevation produces a rise that when multiplied by its overage, and then doubled, is equal to the total elevation.

Any help would, as always, be much appreciated.