Hey guys, really struggling understanding how to go about this question :/
The full question is:
"Let SIN(α)=a, where α is an element of (0, pi/2). Find, in terms of α, two values of x in [0, 2pi] which satisfies the equation SIN(x)= -a"
I can see that SIN(x)=-SIN(α), but where do I go from here?
We know that α is an angle in the 1st Quadrant, hence SIN(α) is positive.
The answers are: pi+α, and 2pi-α
Thanks in advance for any guidance,