Hey guys, really struggling understanding how to go about this question :/

The full question is:

"Let SIN(α)=a, where α is an element of (0, pi/2). Find, in terms of α, two values ofxin [0, 2pi] which satisfies the equation SIN(x)= -a"

I can see that SIN(x)=-SIN(α), but where do I go from here?

We know that α is an angle in the 1^{st}Quadrant, hence SIN(α) is positive.

The answers are: pi+α, and 2pi-α

Thanks in advance for any guidance,

Regards

Smeato