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Thread: Problems in three dimensions

  1. #1
    wxr
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    Unhappy Problems in three dimensions

    Standing due south of a tower 50m high, the angle of elevation of the top is 26o. What is the angle of elevation after walking a distance of 120m due east?
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    Re: Problems in three dimensions

    starting distance South of the tower's base is $d_1= \dfrac{50}{\tan(26^\circ)}$ meters

    Moving 120m East, the new distance from the tower's base is $d_2=\sqrt{d_1^2 + 120^2}$ meters.

    new angle of elevation = $\arctan\left(\dfrac{50}{d_2}\right)$
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  3. #3
    wxr
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    Re: Problems in three dimensions

    Thanks for the help! But I haven't learned this method yet..
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    Re: Problems in three dimensions

    All I used was basic right triangle trig and Pythagoras ...

    If you're not familiar with those two concepts, you'll have to provide a clue as to what method(s) you do know.
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  5. #5
    wxr
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    Re: Problems in three dimensions

    Can i have a diagram if possible? Because i dont really know where does the 50/tan(26) come from, thanks.
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    Re: Problems in three dimensions

    Ok ...
    Attached Thumbnails Attached Thumbnails Problems in three dimensions-img_1510.png  
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    Re: Problems in three dimensions

    3D sketch for the entire problem ... which you need to be able to do yourself

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  8. #8
    wxr
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    Re: Problems in three dimensions

    Thankss!!
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