1. rearanging trig equation

0.04=0.08cos(12.57t)

arccos(0.04/0.08)/12.57=t

t=4.77

is this correct?
If yes, why the solution on the book is t=0.083?

2. Re: rearanging trig equation

Originally Posted by cxz7410123
0.04=0.08cos(12.57t)
cos(12.57t) = 1/2

3. Re: rearanging trig equation

Originally Posted by cxz7410123
0.04=0.08cos(12.57t)
is this correct?
If yes, why the solution on the book is t=0.083?
See HERE.

4. Re: rearanging trig equation

Originally Posted by cxz7410123
0.04=0.08cos(12.57t)

arccos(0.04/0.08)/12.57=t

t=4.77

is this correct?
If yes, why the solution on the book is t=0.083?

5. Re: rearanging trig equation

$0.04=0.08\,\cos(12.57t)$

$\dfrac{0.04}{0.08}=\cos(12.57t)$

$\dfrac{1}{2}=\cos(12.57t)$

$\cos^{-1}\dfrac{1}{2}=(12.57t)$

$60\times\dfrac{\pi}{180}=(12.57t)$

$1.047=12.57t$

$t=0.083$