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Math Help - trig integration help!

  1. #1
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    trig integration help!

    i am taking the integral of (sin(mx))^3 i.e. sin cubed of mx. i used broke it into sin squared mx times sin mx and then used substitution. i set u equal to cos(mx) and got -m^-1 du = sin (mx) dx

    for the answer i got: -m^-1 * cos(mx) + (3*m)^-1 * cos^3(mx) + c
    is this correct?
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by pcgamer03 View Post
    i am taking the integral of (sin(mx))^3 i.e. sin cubed of mx. i used broke it into sin squared mx times sin mx and then used substitution. i set u equal to cos(mx) and got -m^-1 du = sin (mx) dx

    for the answer i got: -m^-1 * cos(mx) + (3*m)^-1 * cos^3(mx) + c
    is this correct?
    yes
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