What's the maximum value of if (angles of triangle...).

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- Jan 19th 2008, 11:09 AMjames_bondFind the maximum
What's the maximum value of if (angles of triangle...).

- Jan 19th 2008, 11:56 AMgalactus
I didn't look at this at length, but you may try expanding it out to:

Now, since perhaps you can simplify it down further. - Jan 19th 2008, 02:09 PMgalactus
I took a closer look at your problem and, if I am correct, it has an interesting

max and min. I got as the max and

as the min. It's related to The Golden Ratio.

We can see from differentiating or graphing that the max occurs at

Unless I made a mistake. Check it out. Interesting solution if correct. - Jan 20th 2008, 02:05 AMjames_bond
- Jan 20th 2008, 05:25 AMgalactus
That is just an expansion/identity of your expression.

Since and , I just excluded it. - Jan 20th 2008, 06:49 AMjames_bondQuote:

(And could you please use \sin \cos etc in LaTeX so nobody could even think of variables and it's nicer. Thx) - Jan 20th 2008, 07:09 AMgalactus
DUH. I'm sorry. I misread the problem and it was all for naught. (Fubar)(Headbang)

Let me get back to you.

What do you mean use sin and cos in LaTex?. That's what I've been doing. - Jan 20th 2008, 07:16 AMgalactus
In that event, perhaps we can proceed in the same manner except use:

or let and use:

Differentiate wrt A and B and solve. - Jan 20th 2008, 08:23 AMjames_bond
- Jan 20th 2008, 02:19 PMgalactus
Hey JB. What did you get as a max value?. 9/8?.

- Jan 21st 2008, 06:01 AMjames_bond
Yes but I'm just guessing - I can't prove it :(

- Jan 21st 2008, 08:55 AMgalactus
Sub , then you have two variables. Take the derivatives wrt to A and B and whittle it down.

- Jan 23rd 2008, 11:08 AMJaneBennet

So

The maximum value of is . Hence the maximum value of is .