I'm having trouble proving this problem:
sec+cot/sec=1+csc-sin
Please help!
1) Don't post your problem twice.
2) There is no such thing as "sin", the argument is missing.
3) Don't forget brackets, your expression is wrong now.
Now, let's see
$\displaystyle
\frac{{\sec x + \cot x}}{{\sec x}} = 1 + \frac{{\cot x}}{{\sec x}} = 1 + \frac{{\frac{{\cos x}}{{\sin x}}}}{{\frac{1}{{\cos x}}}} = 1 + \frac{{\cos ^2 x}}{{\sin x}}
$
$\displaystyle
1 + \frac{{\cos ^2 x}}{{\sin x}} = 1 + \frac{{1 - \sin ^2 x}}{{\sin x}} = 1 + \frac{1}{{\sin x}} - \sin x
$
Since 1/sin(x) = csc(x), we have what we wanted: LHS = RHS.