Originally Posted by

**killasnake** Hi can someone check this to see if it's correct.

(4-3i) into Trig form

r= Sqrt (4^2+(-3)^2

r= Sqrt (25)

r= 5

tan = -(3/4) = -.01309

arctan = -.74995

2pi -.74995

= 5.5332

*Z= 5 (cos 5.5332 + i sin 5.5332) *

I got confused with the Demoive question

(11+i)^6

r= Sqrt (11^2+1)

r= Sqrt (122)

tan 1/11 = .001586 <----- Is this right?

arctan (.001586) = .09087103

2pi + .09087103

= 6.19231

Put it into Trig form

Z= Sqrt(122) (cos 6.19231 + i sin 6.19231)

Demoiver's

z^6 = Sqrt (122)^6 (cos 6.19231 + i sin 6.19231) ......

First I don't even know if that is right. Also, if it is right I do not know the next step to completing the problem.

Thanks