r=2cos(theta) r=2(x/r) r^2=2x x^2+y^2=2x x= rcos(theta) the answer in the book is (x-1)^2+y^2=1
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Originally Posted by math951 r=2cos(theta) r=2(x/r) r^2=2x x^2+y^2=2x x= rcos(theta) the answer in the book is (x-1)^2+y^2=1 $r = 2 \cos(\theta)$ $r^2 = 2r \cos(\theta)$ $x^2 + y^2 = 2x$ $x^2-2x +y^2 = 0$ $(x-1)^2 -1 + y^2 = 0$ $(x-1)^2 + y^2 = 1$
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