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Math Help - Trig Help

  1. #1
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    Trig Help

    can someone help me with prove this problem? I feel really stupid because I know it's easy but my brain is fried at the moment. Thanks!

    Prove the identity.

    secx-1/1-cosx=secx
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  2. #2
    TD!
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    I assume there are some brackets missing...

    <br />
\frac{{\sec x - 1}}<br />
{{1 - \cos x}} = \frac{{\frac{1}<br />
{{\cos x}} - 1}}<br />
{{1 - \cos x}} = \frac{{\frac{{1 - \cos x}}<br />
{{\cos x}}}}<br />
{{1 - \cos x}} = \frac{1}<br />
{{\cos x}} = \sec x<br />
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  3. #3
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    Thank you very much. I understand it now.
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  4. #4
    TD!
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    You're welcome.

    In such problems, convert everything to the same trig function - if possible - and simplify. Like here, convert the given sec(x) to 1/cos(x) and do some algebraic simplifications (on the fraction).
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