can someone help me with prove this problem? I feel really stupid because I know it's easy but my brain is fried at the moment. Thanks! Prove the identity. secx-1/1-cosx=secx
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I assume there are some brackets missing... $\displaystyle \frac{{\sec x - 1}} {{1 - \cos x}} = \frac{{\frac{1} {{\cos x}} - 1}} {{1 - \cos x}} = \frac{{\frac{{1 - \cos x}} {{\cos x}}}} {{1 - \cos x}} = \frac{1} {{\cos x}} = \sec x $
Thank you very much. I understand it now.
You're welcome. In such problems, convert everything to the same trig function - if possible - and simplify. Like here, convert the given sec(x) to 1/cos(x) and do some algebraic simplifications (on the fraction).
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