Math Help - Trig Help

1. Trig Help

can someone help me with prove this problem? I feel really stupid because I know it's easy but my brain is fried at the moment. Thanks!

Prove the identity.

secx-1/1-cosx=secx

2. I assume there are some brackets missing...

$
\frac{{\sec x - 1}}
{{1 - \cos x}} = \frac{{\frac{1}
{{\cos x}} - 1}}
{{1 - \cos x}} = \frac{{\frac{{1 - \cos x}}
{{\cos x}}}}
{{1 - \cos x}} = \frac{1}
{{\cos x}} = \sec x
$

3. Thank you very much. I understand it now.

4. You're welcome.

In such problems, convert everything to the same trig function - if possible - and simplify. Like here, convert the given sec(x) to 1/cos(x) and do some algebraic simplifications (on the fraction).