can someone help me with prove this problem? :confused: I feel really stupid because I know it's easy but my brain is fried at the moment. Thanks! :D

Prove the identity.

secx-1/1-cosx=secx

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- Apr 17th 2006, 11:17 AMReadingChickTrig Help
can someone help me with prove this problem? :confused: I feel really stupid because I know it's easy but my brain is fried at the moment. Thanks! :D

Prove the identity.

secx-1/1-cosx=secx - Apr 17th 2006, 11:19 AMTD!
I assume there are some brackets missing...

$\displaystyle

\frac{{\sec x - 1}}

{{1 - \cos x}} = \frac{{\frac{1}

{{\cos x}} - 1}}

{{1 - \cos x}} = \frac{{\frac{{1 - \cos x}}

{{\cos x}}}}

{{1 - \cos x}} = \frac{1}

{{\cos x}} = \sec x

$ - Apr 17th 2006, 11:23 AMReadingChick
Thank you very much. I understand it now.

- Apr 17th 2006, 11:25 AMTD!
You're welcome.

In such problems, convert everything to the same trig function - if possible - and simplify. Like here, convert the given sec(x) to 1/cos(x) and do some algebraic simplifications (on the fraction).