And then another question... I don't get where my teacher gets this stuff...
(x-4)(x-2)=(x-3)(x-5)-A(x-3)-B(x-4) is an identity in x, find the values of A and B.
Any and all help is appreciated!
AB = AE because triangle AEB is equilateral.
AD = AB because ABCD is a square.
AD = AE because AD = AB = AE.
Thus triangle EAD is isosceles.
Thus angle ADE = angle AED.
Angle DAE is the complement of angle EAB because the interior angles of a square are right angles.
Angle EAB is 60 degrees because triangle AEB is equilateral.
Thus angle DAE is 90 - 60 = 30 degrees.
Call angle AED x. Then 30 + x + x = 180 because the sum of the interior angles of a triangle is 180 degrees.
Solving this equation I get that x = 75, so angle AED = angle ADE= 75 degrees.
-Dan
This really should have gone in its own thread. See rule #15 here.
Expanding
Collecting like terms:
In order for this expression to be 0 for all x we must have the coefficients of all powers of x equal to 0. So
and
Can you take things from here?
-Dan