The problem is
Determine the exact value of
sin (2 arccos (8/17))
The triangle for sin (arccos x) = sqroot(1-x^2). I have no idea how the answer is (240/289).
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Hello, shogunhd! Determine the exact value of: .
So, is in a right triangle with: . . . Using Pythagorus, we find that: .
The problem becomes: .
Originally Posted by shogunhd Determine the exact value of
sin (2 arccos (8/17)) Similar to this problem.
Plug and you're done.
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