1. ## Im I wrong or is the answer not available

Iv tried multiple times and I cant get an answer that is listed. What gives?

2. ## Re: Im I wrong or is the answer not available

Originally Posted by thatsmessedup
Iv tried multiple times and I cant get an answer that is listed. What gives?

Your work looks good to me. What is the answer supposed to be?

-Dan

3. ## Re: Im I wrong or is the answer not available

typo ... should be $\displaystyle \cos{\theta} = -\frac{7}{25}$

use that and the correct solution is there.

4. ## Re: Im I wrong or is the answer not available

You would not imagine how many extra hours iv spent trying to solve typos! arrrrggggg.

5. ## Re: Im I wrong or is the answer not available

I did the problem using the formulas for sin(2x) and cos(2x) and did not get any of the listed answers.

6. ## Re: Im I wrong or is the answer not available

correcting the typo ...

$\displaystyle \cos{t} = -\frac{7}{25}$ , $\displaystyle \sin{t} = \frac{24}{25}$

$\displaystyle \tan(2t) = \frac{\sin(2t)}{\cos(2t)} = \frac{2\sin{t}\cos{t}}{2\cos^2{t} - 1}$

sub in the values for sine and cosine yields

$\displaystyle \tan(2t) = \frac{336}{527}$