Hi, I was wondering if anyone could help me evaluate this trig function sin(Cos^-1(5/13) + Sin^-1(3/5)) =
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would this be working it to the right way? using the Sum and Differences forumla of sin(x+y)=sinXcosY+cosXsinY Sin(Cos^-1(5/13))Cos(Sin^-1)) + Cos(Cos^-1(5/13))Sin(Sin^-1(3/5))
Originally Posted by drewms64 would this be working it to the right way? using the Sum and Differences forumla of sin(x+y)=sinXcosY+cosXsinY Sin(Cos^-1(5/13))Cos(Sin^-1)) + Cos(Cos^-1(5/13))Sin(Sin^-1(3/5)) Looks like a good start to me! -Dan
Draw out your right triangle and work from there. The first term can be found easily this way.
I was able to use the right triangle way and get Code: SIN(COS^-1(5/13))COS(SIN^-1(3/5)) + (5/13)(3/5) (12/13)(4/5) + (5/13)(3/5) (48/65) + (15/65) = 63/65 thanks for the help
SIN(COS^-1(5/13))COS(SIN^-1(3/5)) + (5/13)(3/5) (12/13)(4/5) + (5/13)(3/5) (48/65) + (15/65) = 63/65
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