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Math Help - Evaluating This Trig Function

  1. #1
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    Evaluating This Trig Function

    Hi, I was wondering if anyone could help me evaluate this trig function

    sin(Cos^-1(5/13) + Sin^-1(3/5)) =
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  2. #2
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    would this be working it to the right way?

    using the Sum and Differences forumla of
    sin(x+y)=sinXcosY+cosXsinY

    Sin(Cos^-1(5/13))Cos(Sin^-1)) + Cos(Cos^-1(5/13))Sin(Sin^-1(3/5))
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  3. #3
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    Quote Originally Posted by drewms64
    would this be working it to the right way?

    using the Sum and Differences forumla of
    sin(x+y)=sinXcosY+cosXsinY

    Sin(Cos^-1(5/13))Cos(Sin^-1)) + Cos(Cos^-1(5/13))Sin(Sin^-1(3/5))
    Looks like a good start to me!

    -Dan
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  4. #4
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    Draw out your right triangle and work from there. The first term can be found easily this way.
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  5. #5
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    I was able to use the right triangle way and get

    Code:
    SIN(COS^-1(5/13))COS(SIN^-1(3/5)) + (5/13)(3/5)
    
    (12/13)(4/5) + (5/13)(3/5)
    
    (48/65) + (15/65) = 63/65
    thanks for the help
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