1. ## trig equation

solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi

2. Originally Posted by c_323_h
solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi
sec(x)=2

Now, sec=1/cos

Thus cos(x)=1/2.

So for what values of x is cos(x)=1/2?

-Dan

3. Originally Posted by c_323_h
solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi
That means,
$\sec x=2$
because secant is reciprocal function of cosine we have,
$\cos x=\frac{1}{2}$ for $0
Thus,
$x=\frac{\pi}{6},\frac{11\pi}{6}$

4. i've got pi/3 and 5pi/3

5. Originally Posted by c_323_h
i've got pi/3 and 5pi/3
Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay...

-Dan

6. Originally Posted by topsquark
Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay...

-Dan
No I am so tired now. Not really realizing what I am doing.
If I make another mistake I am leaving this site for today.

7. Originally Posted by ThePerfectHacker
No I am so tired now. Not really realizing what I am doing.
If I make another mistake I am leaving this site for today.
It's okay. We still love you. Get some sleep for me!

-Dan