solve the trig equation sec(x)-2=0 for exact solutions in the interval 0<= x <= 2pi
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Originally Posted by c_323_h solve the trig equation sec(x)-2=0 for exact solutions in the interval 0<= x <= 2pi sec(x)=2 Now, sec=1/cos Thus cos(x)=1/2. So for what values of x is cos(x)=1/2? -Dan
Originally Posted by c_323_h solve the trig equation sec(x)-2=0 for exact solutions in the interval 0<= x <= 2pi That means, because secant is reciprocal function of cosine we have, for Thus,
i've got pi/3 and 5pi/3
Originally Posted by c_323_h i've got pi/3 and 5pi/3 Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay... -Dan
Originally Posted by topsquark Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay... -Dan No I am so tired now. Not really realizing what I am doing. If I make another mistake I am leaving this site for today.
Originally Posted by ThePerfectHacker No I am so tired now. Not really realizing what I am doing. If I make another mistake I am leaving this site for today. It's okay. We still love you. Get some sleep for me! -Dan
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