Thread: trig equation

solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi

Originally Posted by c_323_h

solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi

sec(x)=2

Now, sec=1/cos

Thus cos(x)=1/2.

So for what values of x is cos(x)=1/2?

-Dan

Originally Posted by c_323_h

solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi

That means,

because secant is reciprocal function of cosine we have,
for
Thus,

i've got pi/3 and 5pi/3

Originally Posted by c_323_h

i've got pi/3 and 5pi/3

Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay...

-Dan

Originally Posted by topsquark

Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay...

-Dan

No I am so tired now. Not really realizing what I am doing.
If I make another mistake I am leaving this site for today.

Originally Posted by ThePerfectHacker

No I am so tired now. Not really realizing what I am doing.
If I make another mistake I am leaving this site for today.

It's okay. We still love you. Get some sleep for me!

-Dan