solve the trig equation sec(x)-2=0 for exact solutions in the interval

0<= x <= 2pi

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- Mar 26th 2006, 02:34 PMc_323_htrig equation
solve the trig equation sec(x)-2=0 for exact solutions in the interval

0<= x <= 2pi - Mar 26th 2006, 03:39 PMtopsquarkQuote:

Originally Posted by**c_323_h**

Now, sec=1/cos

Thus cos(x)=1/2.

So for what values of x is cos(x)=1/2?

-Dan - Mar 26th 2006, 03:39 PMThePerfectHackerQuote:

Originally Posted by**c_323_h**

$\displaystyle \sec x=2$

because secant is reciprocal function of cosine we have,

$\displaystyle \cos x=\frac{1}{2}$ for $\displaystyle 0<x<2\pi$

Thus,

$\displaystyle x=\frac{\pi}{6},\frac{11\pi}{6}$ - Mar 26th 2006, 03:45 PMc_323_h
i've got pi/3 and 5pi/3

- Mar 26th 2006, 04:17 PMtopsquarkQuote:

Originally Posted by**c_323_h**

-Dan - Mar 26th 2006, 04:22 PMThePerfectHackerQuote:

Originally Posted by**topsquark**

If I make another mistake I am leaving this site for today. - Mar 26th 2006, 04:26 PMtopsquarkQuote:

Originally Posted by**ThePerfectHacker**

-Dan