could anyone please show how to solve this step by step. All help is appreciated! solve the equation for 0< x< 2 pi . sin^2 X = 3 cos^2 X thanks!!
Follow Math Help Forum on Facebook and Google+
I'd make a substitution and see what dropped out. $\displaystyle \cos^{2}(x)\;=\;1\;-\;\sin^{2}(x)$
sin ^2 x - 3cos^2 x = 0 1-cos ^2 x - 3cos ^2x= 0 4 cos ^2 x -1 = 0 cos ^2 x = 1/4 cos x = 1/2 using special angles you find that its 60 and 300 degrees.
View Tag Cloud