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Thread: Trig functions..Simplifying....

  1. November 23rd 2007, 07:41 AM #1
    aikenfan
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    Trig functions..Simplifying....

    The equation given is right next to each number...all work under that is mine...I believe the first four should be correct, but I am having trouble from number 5-8...could someone please assist me?
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  2. November 23rd 2007, 08:37 AM #2
    TKHunny
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    5 & 6 are easily shown with the Pythagorean Identity.

    In 5, there is a preponderance of sin(x), so solve for \cos^{2}(x)\;=\;1\;-\;\sin^{2}(x) and substitute. You will be left with a bunch of sines that you can handle.

    In 6, there is a preponderance of cos(x), so solve for \sin^{2}(x)\;=\;1\;-\;\cos^{2}(x) and substitute. You will be left with a bunch of cosines that you can handle.
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