# [Urgent] Solving Trig Equations

• Nov 21st 2007, 03:18 PM
Macleef
[Urgent] Solving Trig Equations
Solve each equation for $0 \leq \theta \leq 360$

$3sinx = 2cos^{2}x$

30 and 150 degrees

Nevermind, solved it
• Nov 21st 2007, 03:32 PM
Krizalid
Quote:

Originally Posted by Macleef
$3sinx = 2cos^{2}x$

$3sinx = 1 - 2sin^{2}x$

You ate a 2, it should be $3\sin x=2-2\sin^2x.$

• Nov 21st 2007, 03:34 PM
Macleef
Quote:

Originally Posted by Krizalid
You ate a 2, it should be $3\sin x=2-2\sin^2x.$

What? I don't get what you mean by "you ate a 2"?
• Nov 21st 2007, 03:43 PM
Krizalid
You forgot a 2.

Now, can you solve the remaining problem?
• Nov 21st 2007, 03:44 PM
Plato
Can you solve $2z^2 + 3z - 1 = 0$?
Then let $\sin (x) = z$.
• Nov 21st 2007, 03:46 PM
Macleef
Quote:

Originally Posted by Plato
Can you solve $2z^2 + 3z - 1 = 0$?
Then let $\sin (x) = z$.

You can't solve for that equation...but I can't say there aren't any solutions because there are and I don't know what I'm doing wrong
• Nov 21st 2007, 03:50 PM
Macleef
Quote:

Originally Posted by Krizalid
You forgot a 2.

Now, can you solve the remaining problem?

I still don't know what you're saying? I didn't forget any 2
• Nov 21st 2007, 04:11 PM
Plato
Quote:

Originally Posted by Macleef
You can't solve for that equation...but I can't say there aren't any solutions because there are and I don't know what I'm doing wrong

Sorry to learn that. Have you considered that you may not be ready to do this problem?
If I were you, I would ask myself why I am being asked to do this level of problem?
Do you have the necessary mathematical background to tackle a problem at this level?