BG,Y and point of landing helcopter makes rectangular triangle. Use trigonometry
A more common phrase would be "right triangle". But, yes, knowing the angle, the length of the hypotenuse is 60 and the near leg is 40t where t is the number of hours the helicopter is flying, you can find the length of the "opposite leg" using trigonometry.
If I draw a right triangle, I can find that the hypotenuse through
h = 60 / (cos 22) = 65 mi (rounded)
speed = distance / time
time = 65 mi / (40 mi/h) = 1.625 hour = 98 minutes (rounded)
Due to my calculations, the helicopter will be closest to Ypsilanti at 4:38 P.M.
But the book says 4:23 P.M.
What am I missing?
Sorry guys, I made the hypotenuse the wrong Leg. If the hypotenuse is the 60 miles distance between the two cities then the answer will be 4:23 P.M.
My Question now is
How did we manage to make the 60 miles distance between them, is the hypotenuse?