$3\sin(x)=\sin(x)+1$
$2\sin(x)=1$
$\sin(x)=\dfrac{1}{2}$
$x=30deg, 150deg$
Are you sure you typed the equation correctly? I don't see any need for quadratics.
I don't know where to start. Here is the question
Using a calculator, determine the solutions for each equation, to two decimal places, on the interval 0< x < 360 (it's equal to or greater than and equal to or less than I don't know how to put the line underneath the signs sorry)
This is the equation 3Sin x = Sin x +1
I tried to put everything on one side hoping I could factor and got 3Sin x -Sin x - 1 = 0
after using the quadratic formula I got the wrong answers
The answers should be X = 0.52 or 2.62 I don't know how they got that.