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Math Help - Finding solutions for the Trig Equation

  1. #1
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    Finding solutions for the Trig Equation

    I don't know where to start. Here is the question

    Using a calculator, determine the solutions for each equation, to two decimal places, on the interval 0< x < 360 (it's equal to or greater than and equal to or less than I don't know how to put the line underneath the signs sorry)

    This is the equation 3Sin x = Sin x +1


    I tried to put everything on one side hoping I could factor and got 3Sin x -Sin x - 1 = 0

    after using the quadratic formula I got the wrong answers

    The answers should be X = 0.52 or 2.62 I don't know how they got that.
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  2. #2
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    Re: Finding solutions for the Trig Equation

    $3\sin(x)=\sin(x)+1$

    $2\sin(x)=1$

    $\sin(x)=\dfrac{1}{2}$

    $x=30deg, 150deg$

    Are you sure you typed the equation correctly? I don't see any need for quadratics.
    Thanks from ForeverConfused and topsquark
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  3. #3
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    Re: Finding solutions for the Trig Equation

    Quote Originally Posted by romsek View Post
    $3\sin(x)=\sin(x)+1$

    $2\sin(x)=1$

    $\sin(x)=\dfrac{1}{2}$

    $x=30deg, 150deg$

    Are you sure you typed the equation correctly? I don't see any need for quadratics.
    omg I'm stupid. Thanks. I misunderstood the question
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