# Thread: Finding solutions for the Trig Equation

1. ## Finding solutions for the Trig Equation

I don't know where to start. Here is the question

Using a calculator, determine the solutions for each equation, to two decimal places, on the interval 0< x < 360 (it's equal to or greater than and equal to or less than I don't know how to put the line underneath the signs sorry)

This is the equation 3Sin x = Sin x +1

I tried to put everything on one side hoping I could factor and got 3Sin x -Sin x - 1 = 0

The answers should be X = 0.52 or 2.62 I don't know how they got that.

2. ## Re: Finding solutions for the Trig Equation

$3\sin(x)=\sin(x)+1$

$2\sin(x)=1$

$\sin(x)=\dfrac{1}{2}$

$x=30deg, 150deg$

Are you sure you typed the equation correctly? I don't see any need for quadratics.

3. ## Re: Finding solutions for the Trig Equation

Originally Posted by romsek
$3\sin(x)=\sin(x)+1$

$2\sin(x)=1$

$\sin(x)=\dfrac{1}{2}$

$x=30deg, 150deg$

Are you sure you typed the equation correctly? I don't see any need for quadratics.
omg I'm stupid. Thanks. I misunderstood the question