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Math Help - Trigonometry HELL!

  1. #1
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    Trigonometry HELL!

    I'm in summerschool right now and in regular school the teachers never taught us about trigonometry, yet i got 2 trigonomical questions thrown at me by my summerschool proffesor. I have ABSOLUTLEY no clue of what i am supposed to do.

    The first problem:

    I am to find out which of the four alternatives below is the same as 267o, I believe several alternatives might be the awnser but i am not entirely sure:

    1. 1347o
    2. 329*pi/60
    3. -993o
    4. -91*pi/60

    What i was able to do was transform the 267o to radians, 89*pi/60. After that i tried all the formulas for both degrees and radians and nothing worked.

    The second problem:

    I am to find the distance between the point (-5, 7) and the point were this line: -8x+4y=16 intercepts the x-axis.
    The awnser is supposed to be sqrt a where a is a whole number.
    I have tried the distance formula on this many times and failed, i could really use some help!
    Last edited by Foxtrot; July 12th 2014 at 06:27 AM.
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  2. #2
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    Re: Trigonometry HELL!

    1) any angle measure, $\theta$, given in degrees, is equivalent to $\theta \pm 360$ degrees.

    2) first where does the line intercept the x axis. It does so when $y=0$. Plugging that in it should be clear this occurs at $x=-2$

    Thus we have the points (-2,0) and (-5,7)

    $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=$

    Spoiler:
    $\sqrt{(-5-(-2))^2+(7-0)^2}=\sqrt{(-3)^2+7^2}=\sqrt{9+49}=\sqrt{58}$
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  3. #3
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    Re: Trigonometry HELL!

    At the first one, what does that "0" sign mean? is it part of a formula or something? As i said i hardly know anything about trigonometry :/
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  4. #4
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    Re: Trigonometry HELL!

    It is not a "0", it is the Greek letter "theta", \theta. It is used to indicate the angle.
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  5. #5
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    Re: Trigonometry HELL!

    Okay got it, il try again! Thx guys
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