1. ## Trigonometry HELL!

I'm in summerschool right now and in regular school the teachers never taught us about trigonometry, yet i got 2 trigonomical questions thrown at me by my summerschool proffesor. I have ABSOLUTLEY no clue of what i am supposed to do.

The first problem:

I am to find out which of the four alternatives below is the same as 267o, I believe several alternatives might be the awnser but i am not entirely sure:

1. 1347o
2. 329*pi/60
3. -993o
4. -91*pi/60

What i was able to do was transform the 267o to radians, 89*pi/60. After that i tried all the formulas for both degrees and radians and nothing worked.

The second problem:

I am to find the distance between the point (-5, 7) and the point were this line: -8x+4y=16 intercepts the x-axis.
The awnser is supposed to be $sqrt$ a where a is a whole number.
I have tried the distance formula on this many times and failed, i could really use some help!

2. ## Re: Trigonometry HELL!

1) any angle measure, $\theta$, given in degrees, is equivalent to $\theta \pm 360$ degrees.

2) first where does the line intercept the x axis. It does so when $y=0$. Plugging that in it should be clear this occurs at $x=-2$

Thus we have the points (-2,0) and (-5,7)

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=$

Spoiler:
$\sqrt{(-5-(-2))^2+(7-0)^2}=\sqrt{(-3)^2+7^2}=\sqrt{9+49}=\sqrt{58}$

3. ## Re: Trigonometry HELL!

At the first one, what does that "0" sign mean? is it part of a formula or something? As i said i hardly know anything about trigonometry :/

4. ## Re: Trigonometry HELL!

It is not a "0", it is the Greek letter "theta", $\theta$. It is used to indicate the angle.

5. ## Re: Trigonometry HELL!

Okay got it, il try again! Thx guys