Results 1 to 4 of 4

- Jul 1st 2014, 11:43 PM #1

- Joined
- Jun 2014
- From
- United Kingdom
- Posts
- 5

- Jul 2nd 2014, 01:18 AM #2

- Joined
- Nov 2013
- From
- California
- Posts
- 5,146
- Thanks
- 2187

## Re: Can you help me.....

$3 \tan\left(\dfrac x 2\right)+3=0$

$3 \tan\left(\dfrac x 2\right)=-3$

$\tan\left(\dfrac x 2\right)=-1$

$\dfrac x 2 =\arctan(-1)$

$\dfrac x 2 = \dfrac {3\pi}{4} + 2k\pi~~k\in \mathbb{Z}$

OR

$\dfrac x 2 = \dfrac {7\pi}{4} + 2k\pi~~k\in \mathbb{Z}$

$x = \dfrac{3\pi}{2}+4k\pi~~k\in \mathbb{Z}$

OR

$x = \dfrac{7\pi}{2}+4k\pi~~k\in \mathbb{Z}$

- Jul 18th 2014, 08:25 PM #3

- Joined
- Jul 2014
- From
- NYC
- Posts
- 8

## Re: Can you help me.....

Romsek, please take a look at the following video, also Miroslaw who's teaching it has a lot of great resources regarding your question, Cheers Karol

https://www.youtube.com/watch?v=2P2_...KpJncYFke-V0xQ

- Jul 18th 2014, 08:27 PM #4

- Joined
- Jul 2014
- From
- NYC
- Posts
- 8

## Re: Can you help me.....

Also, please check the following web link

Finally Understand :: Math tutoring, Electronics tutoring, Test prep, SAT, GED, Accuplacer, Virtual Learning Center, Online tutoring, tutorials, online degree, video lessons, academy, college, mathematics, free tutoring, free tutorials, resources for

Cheers,

Karol