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Math Help - Can you help me.....

  1. #1
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    Can you help me.....


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  2. #2
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    Re: Can you help me.....

    Quote Originally Posted by SammyLee View Post

    $3 \tan\left(\dfrac x 2\right)+3=0$

    $3 \tan\left(\dfrac x 2\right)=-3$

    $\tan\left(\dfrac x 2\right)=-1$

    $\dfrac x 2 =\arctan(-1)$

    $\dfrac x 2 = \dfrac {3\pi}{4} + 2k\pi~~k\in \mathbb{Z}$

    OR

    $\dfrac x 2 = \dfrac {7\pi}{4} + 2k\pi~~k\in \mathbb{Z}$


    $x = \dfrac{3\pi}{2}+4k\pi~~k\in \mathbb{Z}$

    OR

    $x = \dfrac{7\pi}{2}+4k\pi~~k\in \mathbb{Z}$
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  3. #3
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    Re: Can you help me.....

    Romsek, please take a look at the following video, also Miroslaw who's teaching it has a lot of great resources regarding your question, Cheers Karol
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