(tan/theta) - ((sin/theta)(cos/theta)) / (sin^2/theta) = (tan/theta)
I understand this is as,Originally Posted by cheerleader4life4u
First you can cancel the sines, to get,
Next, express tangent through sine and cosine,
Add fractions,
Recognize the double-angle identities,
Thus,
Your claim that it is equivalent to
is dreadfully wrong.
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Unless you want me to solve for ?