n1 = -n2 so the planes are either coincident or parallel.
the point (4,0,3) is in plane 1
(4,0,3) is also in the second plane when p=-2 and q=-10
and thus the planes are coincident.
Are the two planes r = (4,0,3) + t(-8,1,-9) + u(-1,5,7) and r = (-14,12,-1) + p(1,1,3) + q(-2,1,-1) parallel, coincident, or neither?
So what I did was took the two direction vectors, took the cross product and compared the two normal vectors. The answer is coincident but the normals are not collinear and to me it's neither
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