Please close this thread, solved all problems...
Last edited by Macleef; November 17th 2007 at 08:27 PM.
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Originally Posted by Macleef 1) Prove: sin2x / 1 - cos2x = cotx My Attempt: LS: = 2sinxcosx / - 1 - (1 - 2sin^2x) = 2sinxcosx / - 1 + 2sin^2x = cosx / sinx - 1 Please use parenthesis!! Is there a typo? -1 - 1 = -2, not -1. And if you can't factor a 2 out of everything, then you can't cancel the 2, so the last line here is wrong. The same goes for sin(x). You had the right idea, but you didn't have the details right. -Dan
Thanks I see where I went wrong now, can you also please help with the rest? Edit: I don't know how to use the parenthesis?
Originally Posted by Macleef I don't know how to use the parenthesis? The kid is crying so I can't. You don't know how to use parenthesis??? I'm talking about the difference between vs. You use them to group terms together. -Dan
Originally Posted by topsquark The kid is crying so I can't. You don't know how to use parenthesis??? I'm talking about the difference between vs. You use them to group terms together. -Dan What? The kid is crying so you can't???? I can group them...but not with the latex feature because I don't know how to use it
Hello, Macleef! 4) Prove: . We'll use the identity: . . . . twice. We have: . . . . .
Originally Posted by Soroban Hello, Macleef! We'll use the identity: . . . . twice. We have: . . . . . wow, you lost me -_- from the beginning when you wrote, "we'll use this identity"
Originally Posted by Macleef wow, you lost me -_- from the beginning when you wrote, "we'll use this identity" There are two ways to get at this identity. I'll use the one you will have been likely to see: (The quick way to do this is using a half-angle identity.) -Dan
Originally Posted by Macleef Please close this thread, solved all problems... do not delete your question even after it is answered. it may help someone else
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