Find all points that are equidistant from 6x-12y+15z-9=0 and 12x+9y-20z-19=0. Thanks.
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Ops, wrong section, this should be in geometry.
I would say that since the points are equidistant from the two planes, then they would be equidistant from their normal vectors...
Hello, kicma! Code: : * : * * : * * : * * : * - - - - - - - * - - - - - - - * : * * : * * : * * : * : The solution is a pair of perpendicular planes bisecting the angles formed by the two given planes.
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