Find all points that are equidistant from 6x-12y+15z-9=0 and 12x+9y-20z-19=0.
Thanks.
Hello, kicma!
$\displaystyle \text{Find all points that are equidistant from }\,6x-12y+15z-9\:=\:0$
$\displaystyle \text{ and }\,12x+9y-20z-19\:=\:0.$
The solution is a pair of perpendicular planesCode:: * : * * : * * : * * : * - - - - - - - * - - - - - - - * : * * : * * : * * : * :
bisecting the angles formed by the two given planes.