Please help! I need to find the equation for each of these....I do not understand how to do so...please help...
The Amplitude on 67 looks like it is 3...
How do I solve for the period...If I know that, then I can put it in the equation...
On 68, the amplitude is 2
And 70 also appears to be 2
2pi/K = Period (K is the number in your equation)
2pi/K = pi
Therefore, k = 2, because the two's would cancel out leaving you with just pi. So your equation would be y = 3sin(pi)x . Hope that helps and makes the rest of them easier.
In your graph, you can tell that the period is pi.
but you can't just put pi in your equation, because the "K" value in your equation is not the period, to get the period it is 2pi DIVIDED by K.
2pi/k = pi (you know pi from your graph)
What value of K gives you a period of pi?
2 does, because the twos cancel out and your left with pi as your period.
recall, the general form is
where is the amplitude
is the phase shift
is the vertical shift
is the period, and
is the appropriate graphing interval
thus, if your period is , it means that,
also, your amplitude is 3 here. there is no vertical or phase shifts, thus, you equation for 68 is:
now try 70 again