Please help! I need to find the equation for each of these....I do not understand how to do so...please help...
The Amplitude on 67 looks like it is 3...
How do I solve for the period...If I know that, then I can put it in the equation...
On 68, the amplitude is 2
And 70 also appears to be 2
Well, since you have the amplitude, to figure out the period, as someone already said, you figure out where it repeats. In 67, it looks like it stops at pi. I got this because it repeates twice between 0 and 2pi, so divide that in half, and you get pi for the period. However, when you put it into you equation you must use:
2pi/K = Period (K is the number in your equation)
2pi/K = pi
Therefore, k = 2, because the two's would cancel out leaving you with just pi. So your equation would be y = 3sin(pi)x . Hope that helps and makes the rest of them easier.
The two came from:
In your graph, you can tell that the period is pi.
but you can't just put pi in your equation, because the "K" value in your equation is not the period, to get the period it is 2pi DIVIDED by K.
2pi/k = pi (you know pi from your graph)
What value of K gives you a period of pi?
2 does, because the twos cancel out and your left with pi as your period.
your amplitude is wrong as well as the period
recall, the general form is
where is the amplitude
is the phase shift
is the vertical shift
is the period, and
is the appropriate graphing interval
thus, if your period is , it means that,
also, your amplitude is 3 here. there is no vertical or phase shifts, thus, you equation for 68 is:
now try 70 again