# Math Help - Equation with cos

1. ## Equation with cos

Solve the equation: $2\cos{5x}+2\cos{4x}+2\cos{3x}+2\cos{2x}+2\cos{x}+1 =0$

2. cos(ax) = cos((a-1)x + x)
expand and continue in that fashion

3. Originally Posted by qspeechc
cos(ax) = cos((a-1)x + x)
expand and continue in that fashion
Could you explain it please. I just couldn't solve the for $x$ using only the $\cos(ax) = \cos((a-1)x + x)$. Thx

4. So you have:

2cos5x + 2cos4x + 2cos3x + 2cos2x + 2cosx + 1 = 0

And I said:
cos(ax) = cos((a-1)x + x)
expand and continue in that fashion

So, for instance, lets look at the case where a = 5:

cos5x = cos(4x + x)

Now that is of the form cos(A+B), which we know how to expand:
cos(A+B) = cosA.cosB - sinA.sinB

So, for cos5x:
cos5x = cos(4x + x)
. = cos(4x).cos(x) - sin(4x).sin(x)

And then you can do the same sort of expansions with sin(4x), cos(4x), cos(3x) etc., until you are satisfied you have simplified it enough to solve.