(tan x)^3 + (tan x)^2 - 3(tan x) - 3 = 0
Hello, Jennifer!
$\displaystyle \tan^3\!x + \tan^2\!x - 3\tan x - 3 \:=\: 0$
Factor: .$\displaystyle \tan^2\!x(\tan x + 1) - 3(\tan x + 1) \:=\:0$
Factor: .$\displaystyle (\tan x + 1)(\tan^2x-3) \:=\:0$
Can you continue?