Hi,

Let $\displaystyle 0 \leq \theta \leq \pi$

Find all solutions to:

$\displaystyle \tan(\theta + \dfrac{\pi}{6})=\tan(\pi-\theta) $

Equating the two arguements and solving we find $\displaystyle \theta = \dfrac{5\pi}{12} $. How do I find the other solution?

Thanks