A plane is headed at 270° at a speed of 450MPH. But there is 50MPH wind coming from a bearing of 170°.
a. What is the actual(ground) speed of the plane?
b. What is the bearing of the plane's flight?
The ground speed of the airplane , let it be g
The air speed of the plane, let it be a.
The wind speed, let it be w.
g = a + w. So, just add a + w ( from tip to tail) and you have solved the ground speed of the plane.
The bearing of the plane's flight is the angle (theta) between g and the neighboring vector. Once found, just state the baring. As an idea, usually the answer is in the form of N (some angle + theta) E or W