Dear friends,

The following is the question, I encountered:

What is the number of solutions for the pair of following equations

2 sin^{2}x - cos2x = 0

2 cos^{2}x - 3sinx = 0_{ in the interval [0,2Pi] I added both the equations and I got 2sin2x - 3sinx +1 = 0 For which I thought the solution was 300, 900 and 1500 as the answers. But they say it is wrong?! Is it so? where I went wrong and what is the correct answer? could anyone help me. with warm regards, Aranga }