The following is the question, I encountered:
What is the number of solutions for the pair of following equations
2 sin2x - cos2x = 0
2 cos2x - 3sinx = 0
in the interval [0,2Pi]
I added both the equations and I got 2sin2x - 3sinx +1 = 0
For which I thought the solution was 300, 900 and 1500 as the answers. But they say it is wrong?!
Is it so? where I went wrong and what is the correct answer?
could anyone help me.
with warm regards,