But you have been asked tom use cosine formula and that it
cos A = [b^2 + c^2 - a^2 ]/ 2 bc
cos B = [c^2 + a^2 - b^2 ]/ 2 ac
cos C = [a^2 + b^2 - c^2 ]/ 2 ab
Use these expressions to get the result.
Hey people. Here's the question.
Find the missing parts of the triangle by using the laws of cosines.
What's known is, B=27, a=11, c=22
Solving for b,
Solving for A
Cross multiply.
Solving for C
180-27-49-22=82? Where did I go so wrong. This formula has always seemed to work for me.
But you have been asked tom use cosine formula and that it
cos A = [b^2 + c^2 - a^2 ]/ 2 bc
cos B = [c^2 + a^2 - b^2 ]/ 2 ac
cos C = [a^2 + b^2 - c^2 ]/ 2 ab
Use these expressions to get the result.