The equation for a straight line

Sorry if this is in the wrong section I am not sure what this is categorized as. I have a problem regarding the equation for a straight line. I have the following question and solution but im really not sure if I am right to drop the units. Could anyone help please?

· The equation for a straight line is often used in science to find an unknown without reference to a graph. For a set of data for two quatities, *A* and *B*, where *A* is plotted on the *x*-axis and *B* on the *y*-axis, the gradient of the straight line is 2.3 × 10^{4}m s^{−1} and the intercept on the *y*-axis is 5.8 × 10^{4} m. Using the equation for a straight line (Book 3, Equation 7.12 ) as your starting point, determine the value for *A *when *B* = 6.2 × 10^{5} m. Show all your workings and give your answer in scientific notation and to two significant figures.

Y =mx + c

C = 5.8 × 10^{4} m

M= 2.3 × 10^{4}m s^{−1}

*B* = 6.2 × 10^{5} m

6.2 × 10^{5} = 2.3 × 10^{4} A + 5.8 × 10^{4}

6.2 × 10^{5} - 5.8 × 10^{4} = 2.3 × 10^{4} A

620000 – 58000= 23000 A

562000 = 23000 A

562000 = A

23000

24.434782608695652173913043478261 = A

A = 24 to 2 significant figures.

Re: The equation for a straight line

What seems to be the trouble? You've done everything correctly...

Re: The equation for a straight line

I just wanted to check i am correct in dropping all of the units from the equation? would i need to put some back on to the end for my A value?