DIFFICULT TRIG PROBLEM. WOULD SOMEONE PLEASE HELP ME!!! (Itwasntme) (Doh)

ATTACHED PDF FILE OF THE PROBLEM BELOW...

THANK YOU. MUCH APPRECIATED!!

Printable View

- Nov 20th 2013, 08:43 PMsmyatsallieDifficult trig problem. Would someone please help me!!!
DIFFICULT TRIG PROBLEM. WOULD SOMEONE PLEASE HELP ME!!! (Itwasntme) (Doh)

ATTACHED PDF FILE OF THE PROBLEM BELOW...

THANK YOU. MUCH APPRECIATED!! - Nov 20th 2013, 11:27 PMProve ItRe: Difficult trig problem. Would someone please help me!!!
What have you tried so far?

- Nov 21st 2013, 03:04 PMsmyatsallieRe: Difficult trig problem. Would someone please help me!!!
I attempted making a triangle and solving for the sides; one side measures 20.75m, with a 90 degree angle. Sadly, that is as far as I am able to get. Please help me get started.

Attachment 29788 - Nov 21st 2013, 04:39 PMHallsofIvyRe: Difficult trig problem. Would someone please help me!!!
You will want the boom to miss the top of the roof. It is 10+ (1/2)(8)= 14 m behind the truck. The roof is 9 m wide and has a "pitch of 9/12" so is (9)(9/12)= 27/4= 7.75 m high which means the peak of the roof is 6+ 7.75= 13.75 m above the ground. The boom starts 2.5 m above the ground so the peak of the house is 13.75- 2.5= 11.25 m above the base of the boom. But the hot tub itself is 1 m high so we will need 11.25+ 1= 12.25 m clearance. A right triangle with height 12.25 m and base 14 m has $\displaystyle tan(\theta)= \frac{12.25}{14}$.

- Nov 22nd 2013, 07:32 AMsmyatsallieRe: Difficult trig problem. Would someone please help me!!!
Thank you very much! This really helps.