how to do this: x=0.7*cos(2*pi*200*t); y=0.5*cos(2*pi*1000*t); z=x+y;
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$\displaystyle \cos(2k\pi)=1,\forall k\in\mathbf{Z}$
i need how the way to get one result
What is t? Is integer, rational, real?
x1=07*cos(2*pi*200*t); x2=07*cos(2*pi*1000*t); i need toknow how i do x1+x2
Originally Posted by jsampaio i need how the way to get one result What result? What exactly is your question? Solve for z, solve for t, graph the system, etc. -Dan
is for then put that in fourier is because AM signal modulation.
Originally Posted by jsampaio x1=07*cos(2*pi*200*t); x2=07*cos(2*pi*1000*t); i need toknow how i do x1+x2 $\displaystyle cos(a) + cos(b) = 2cos \left ( \frac{a + b}{2} \right ) ~ cos \left ( \frac{a - b}{2} \right )$ -Dan
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