So Im trying to prove the following inequality 8cos3θ−6cosθ=1.
Ive tried a lot of different things, using substitutions for cos3θ, 2cosθ, pretty much everything and I cant seem to prove it.
Any help would be appreciated.
Thanks
That is neither an inequality nor an identity. WolframAlpha
Now, if you want to know for what values of you have , that is solvable, but not easy. You wind up with a cubic polynomial, which is solvable, but extremely difficult. Solution