Prove:
(tanx)(sinx) / (tanx) + (sinx) = (tanx) - (sinx) / (tanx)(sinx)
What I have so far:
L.S.
= (sinx / cosx) sinx / (sinx / cosx) + sinx
= (sin^2x / cosx) / (sinx + (sinx) (cosx) / cosx)
= (sin^2x / cosx) / (cosx / sinx + sinxcosx)
What do I do now and if I did something wrong, where did I go wrong and how should I go about to fix it?
Prove:
sin^2x - sin^4x = cos^2x - cos^4x
^^^
How did you get "sin^2x(1 - sin^2 x)" in the second line? When I did this, I got "sin^2x (-sin^2x)"
Can you tell me what I did wrong ? I don't know how you got the "1" from ...
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can you continue now?
When I did this, I get:
= (-1 + sinx) (1 + sinx) / (sinx + 1) (sinx +1)
= (-1 + sinx) / (sinx + 1)
And now I'm stumped? I don't know what to do ...
The first one, I remember it now, thanks
And as for the second one,
I'm proving
sinx - 1 / six + 1 = -cos^2x / (sinx + 1)^2
But ... when I did RS = RS, I get this:
= (-1 + sinx) / (sinx + 1)
= - (1 - sinx) / (sinx + 1)
Why do I have a negative in the numerator next to the bracket? How do I remove this to prove the identity?