Solve the following for x: 2sin2(x)=1, 0x2 The solution set is _______ For example if there are 3 solutions, then write {0, pi/3, 3pi/4}
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Originally Posted by bookish12 Solve the following for x: 2sin2(x)=1, 0x2 The solution set is _______ For example if there are 3 solutions, then write {0, pi/3, 3pi/4} Since you just have to check for what values of solutions given above fall into the interval of interest.
Hello, bookish12! I assume that the second "2" is an exponent.
Thank you!!
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